Joy241 Joy241
  • 21-03-2017
  • Mathematics
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jdoe0001 jdoe0001
  • 21-03-2017
[tex]\bf \displaystyle \int \left( 4+\cfrac{5}{t}+\cfrac{10}{t^2} \right)dt\\\\ -----------------------------\\\\ \displaystyle \int 4 \cdot dt+5\int \cfrac{1}{t}\cdot dt+10\int t^{-2}\cdot dt \implies 4t+5ln|t|-\cfrac{10}{t}+C[/tex]
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