Solution:
[tex] \frac{6 {x}^{2} + 7x - 3 }{ - 3 {x}^{2} + x } \\ = \frac{6 {x}^{2} + 9x - 2x - 3 }{ - 3 {x}^{2} + x } \\ = \frac{3x(2x + 3) - 1(2x + 3)}{ - {3x}^{2} + x} \\ = \frac{(2x + 3)(3x - 1)}{x( - 3x + 1)} \\ = \frac{(2x + 3)(3x - 1)}{ - x(3x - 1)} \\ = \frac{(2x + 3)}{x} \\[/tex]
Hope it helps.
Do comment if you have any query.
