b9rundba0byTLillHope b9rundba0byTLillHope

18-08-2016
Mathematics

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[tex](1 x^{2000})(1 x)^{1998}=(2x)^{1999}[/tex]

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18-08-2016

Hello,
[tex]x^{2000}*x^{1998}=2^{1999}*x^{1999}\\ ==\textgreater\ x^{2000+1998}=2^{1999}*x^{1999}\\ ==\textgreater\ x^{2000+1998-1999}=2^{1999}\\ ==\textgreater\ x^{1999}=2^{1999}\\ ==\textgreater\ x=2 [/tex]

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