Answer:
[tex]\large\boxed{\dfrac{7x^2}{6x-10}}[/tex]
Step-by-step explanation:
[tex]\dfrac{7x^2}{2x+6}\div\dfrac{3x-5}{x+3}=\dfrac{7x^2}{2(x+3)}\cdot\dfrac{x+3}{3x-5}\\\\\text{cancel}\ (x+3)\\\\=\dfrac{7x^2}{2}\cdot\dfrac{1}{3x-5}=\dfrac{(7x^2)(1)}{(2)(3x-5)}\\\\\text{use the distributive property}\ a(b-c)=ab-ac\\\\=\dfrac{7x^2}{6x-10}[/tex]
