jacobmclawhorn6976 jacobmclawhorn6976
  • 20-01-2020
  • Chemistry
contestada

Calculate ΔG° for the following reaction from the equilibrium constant at the temperature given. HF(aq)+H2O(l)⟶H3O+(aq)+F−(aq),T=25°C,K=7.2×10−4

Respuesta :

Mergus Mergus
  • 21-01-2020

Answer:

17.93 kJ

Explanation:

The relation between standard Gibbs energy and equilibrium reaction is shown below as:

[tex]\Delta{G^0} =-RT \ln K[/tex]

R is Gas constant having value = 0.008314 kJ / K mol  

Given For the reaction:-

[tex]HF+H_2O\rightarrow H_3O^++F^-[/tex]

temperature, T = [tex]25^oC=[25+273]K=298K[/tex]

[tex]K=7.2\times 10^{-4}[/tex]

Applying in the above equation as:-

[tex]\Delta{G^0} =-0.008314\times 298 \ln(7.2\times 10^{-4})\ kJ=17.93\ kJ[/tex]

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