ANSWER
2x-3=0
and
x+4=0
EXPLANATION
Given that:
[tex]2 {x}^{2} + 5x - 12 = (2x - 3)(x + 4)[/tex]
Then to find roots of
[tex]2 {x}^{2} + 5x - 12 = 0[/tex]
is the same as finding the roots of
[tex](2x - 3)(x + 4) = 0[/tex]
By the zero product property, we must have either,
[tex]2x - 3 = 0 \: or \: x + 4 = 0[/tex]
Hence the equations that must be solved to find the roots are:
2x-3=0
and
x+4=0
Answer:
2x-3=x and x+4=0
Step-by-step explanation:
i just did it on a p e x
