Respuesta :

yousifmona44

[tex] \frac{4v {}^{2} {y}^{5} }{3 {v}^{4} + 5v {}^{2} } [/tex]

your final answer

wegnerkolmp2741o

Answer:

4v^2y^5

-----------------------

(3u^4+5v^2)

Step-by-step explanation:

We can factor out a 2 v^2 out of the numerator and denominator

8v^4y^5  = (2v^2) *4v^2y^5

6u^4v^2 + 10 v^4 = 2v^2 (3u^4+5v^2)

So

8v^4y^5

-----------------

6u^4v^2 + 10 v^4

becomes

(2v^2) *4v^2y^5

-----------------------

2v^2 (3u^4+5v^2)

Canceling 2v^2

4v^2y^5

-----------------------

(3u^4+5v^2)

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