volume of a right hexagonal pyramidd is [tex] \frac{ \sqrt{3} }{2}a^{2}h [/tex] where a is the base side legnth and h=height
side legnth=12
height=36
subsitute
V=[tex] \frac{ \sqrt{3} }{2}(12^{2}) (36) [/tex]
V=[tex] \frac{ \sqrt{3} }{2} (144)(36) [/tex]
V=[tex] \frac{ \sqrt{3} }{2} (5184) [/tex]
V=[tex] \frac{ 5184 \sqrt{3} }{2} [/tex]
V=[tex] 2592 \sqrt{3} [/tex]
V=4489.48 cm^3
