smithaustin8091 smithaustin8091
  • 19-04-2018
  • Mathematics
contestada

If Logx (1 / 8) = - 3 / 2, then x is equal to

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mkryukova19 mkryukova19
  • 19-04-2018
If the equation written like this
[tex]log x^{ \frac{1}{8} } = - \frac{3}{2} then 10^{- \frac{3}{2} } = x^{ \frac{1}{8} } (10^{- \frac{3}{2} })^{8} = ( x^{ \frac{1}{8} } )^{8} x= 10^{-3*4} = 10^{-12} x=10^{-12} If the equation looks like this , then it has the solution x=10^{-12}[/tex]

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