Respuesta :

DhikaFR
Hallo ^_^

Quadratic Equation :
ax² + bx + c = 0

From the task :
x² + 1/20 x = 1/20

Switch sides :
x² + 1/20x - 1/20 = 0

Multiple each sides by 20
20(x² + 1/20x - 1/20) = 0(20)
⇒ 20x² + x - 1 = 0

From that :
a = 20, b = 1 and c = - 1

Solve x using quadratic formula :

[tex]x_1x_2 = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Substitution using the formula :

[tex]x_1x_2 = \frac{-1 \pm \sqrt{1^2-4(20)(-1)}}{2(20)} \\\\ x_1x_2 = \frac{-1 \pm \sqrt{81}}{40} \\\\ x_1x_2 = \frac{-1 \pm 9}{40} \\\\ x_1 = \frac{- 1 + 9}{40} \\\\ x_1 = \frac{8}{40} \\\\ x_1 = \frac{1}{5} \\\\ x_2 = \frac{- 1 - 9}{40} \\\\ x_2 = \frac{-10}{40} \\\\ x_2 = - \frac{1}{4} \\\\ \therefore \boxed{x = \frac{1}{5} \ or \ x =- \frac{1}{4}} [/tex]

Sorry for my bad english :)

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