Respuesta :

keyshawnphillip
x6 – 9x3 + 8 = 0
let u = x^3
u^2 - 9u + 8 = 0 
(u-8)(u-1) = 0
u = 1,8
back substitute 
1 = x^3
8 = x^3

x = 1 , 2

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