QwertyYou QwertyYou
  • 17-04-2018
  • Mathematics
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Express sinθtanθ+cosθ in terms of cosθ

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icedipping
icedipping icedipping
  • 17-04-2018
1/cosθ

sinθtanθ + cosθ = (sinθ)^2/cosθ + cosθ = [(sin)^2 + (cosθ)^2] / cosθ = 1/cosθ

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