To solve the problem, we can use Ohm's law, which states that
[tex]V=IR[/tex]
where
V is the voltage
I is the intensity of current
R is the resistance
Using the data of our problem, I=4 A and [tex]R= 2 \Omega[/tex], we find the voltage:
[tex]V=IR=(4 A)(2 \Omega)=8 V[/tex]
