Answer:
The graph of y=sin x start from x-intercept.
B is correct.
Step-by-step explanation:
Given: [tex]y=\sin x[/tex]
From [tex]x=0\text{ to }x=2\pi[/tex]
We need to find starting point of graph.
Graph will start when x=0
Put x = 0 into y = sin x
We get,
y = sin (0)
y = 0
Starting point is (0,0)
The value of y is 0.
It would be x-intercept of graph.
Hence, The graph of y=sin x start from x-intercept.
