[tex]cos(51)= \frac{y}{9} \\ 0.62932039105=\frac{y}{9}[/tex] multiply by 9 on both sides [tex]5.66388351945=y \\ or \\ 5.7=y[/tex]
Now to find x it's opposite side and the hypotenuse SOH [tex]sin(51)= \frac{x}{9} \\ 0.77714596145= \frac{x}{9} [/tex] Multiply by 9 on both sides [tex]6.99431365311=x \\ or \\ 7=x[/tex]
