Hi there!
[tex] {s}^{2} + {s}^{2} = {d}^{2} [/tex]
According to the Pythagorean Theorem,
[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]
so this statement is true.
Since
[tex] {s}^{2} + {s}^{2} = {d}^{2} [/tex]
and s = 7, then
[tex] {7}^{2} + {7}^{2} = {c}^{2} [/tex]
simply:
49 + 49 = c^2
98 = c^2
c = sqrt (98)
Hope this helps!
