well, we know the solutions are -9 and 9, so, let's just FOIL them then
[tex]\bf \begin{cases}
x=-9\implies &x+9=0\\
x=9\implies &x-9=0
\end{cases}
\\\\\\
(x+9)(x-9)=\stackrel{original~polynomial}{0}\implies x^2+0x-81=0
\\\\\\
x^2\underline{-81}=0\qquad \textit{and we can write }-81=\underline{-103+22}
\\\\\\
x^2\underline{-103+22}=0\implies x^2+22=103[/tex]
