Answer:
[tex]x={\pm}8[/tex]
Step-by-step explanation:
The given quadratic function is:
[tex]f(x)=2x^2-128[/tex]
In order to find the zeros of the quadratic function, we put [tex]f(x)=0[/tex].
thus, we have
[tex]f(x)=0[/tex]
⇒[tex]2x^2-128=0[/tex]
⇒[tex]2x^2=128[/tex]
⇒[tex]x^2=64[/tex]
⇒[tex]x={\pm}8[/tex]
Therefore, the values of x are 8 and -8.
