TeEvalyn865 TeEvalyn865

20-03-2018
Mathematics

contestada

How many 12-digit decimal sequences are there that start and end with a sequence of at least two 3s?

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LammettHash LammettHash

20-03-2018

Four positions of such a sequence are given to be 3s, and we have 10 choices for the remaining eight positions. So the number of such sequences is

[tex]1^4\cdot10^8=10^8=100,000,000[/tex]

or 100 million.

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