How many positive integers $n$ satisfy $\lfloor \sqrt{n} \rfloor = 5$?

Question

20-03-2018
Mathematics

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How many positive integers $n$ satisfy $\lfloor \sqrt{n} \rfloor = 5$?

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carlosego carlosego · Answer 1 · 2018-04-09T14:30:07+02:00

carlosego carlosego

09-04-2018

For this case we have the following equation:
root (n) = 5
Clearing n we have:
n = 5 ^ 2
n = 25
Answer:
A positive integers n that satisfy root (n) = 5 is:
n = 25
(only one integer satisfies the equation given in the problem)

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