Respuesta :

WojtekR
[tex]x^3-4x^2-3x+12=0\\\\x^2\big(x-4\big)-3\big(x-4\big)=0\\\\\big(x^2-3\big)\big(x-4\big)=0\\\\\big(x-\sqrt{3}\big)\big(x+\sqrt{3}\big)\big(x-4\big)=0\\\\\\\boxed{x=\sqrt{3}\qquad\vee\qquad x=-\sqrt{3}\qquad\vee\qquad x=4}[/tex]

Otras preguntas