Respuesta :

TSO
(1,3) and (7,-1)

[tex](\frac{1+7}{2}, \frac{3+(-1)}{2})\\\\(\frac{8}{2}, \frac{2}{2})\\\\\boxed{\bf{(4,1)}}[/tex]

The midpoint of (1,3) and (7,-1) is (4,1).

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