Respuesta :

prosborough198p2ub41
Hello!!

So we can use the equation M1V1=M2V2 to solve for the volume we want.

So we have

12*V1=6*.5

V1=3/12=.250liters or 250mL needed of 12M HCL to make 500mL of 6M HCL solution.

Hope this helps. Any questions please just ask. Thank you!