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What pressure will be exerted by 0.650 mol of a gas at 30.0°C if it is contained in a 0.700L vessel? A) 2340kPa B) 2340atm C) 231kPa D) 231atm

Respuesta :

Rodiak
We are given following information:
n=0.650mol
T=30°C
V=0.700L

First step is to transform these numbers into basic units:
n=0.650mol
T=30°C = 303.15K
V=0.700L = 0.0007m³

We are looking for pressure p.
The formula that connects all these variables is Ideal gas formula:
p * V = n * R * T
where R is gas constant.

We solve this formula for p:
[tex]p= \frac{n*R*T}{V} [/tex]

Now we insert values and calculate the pressure.
[tex]p= \frac{0.650*8.3144598*303.15}{0.0007} \\ p=2340490.7Pa \\ p=2340.5kPa[/tex]

Correct answer is A).
B) is not correct because 1atm = 101325Pa so the value is p=2340490.7 / 101325 = 23.1 atm.

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