21-02-2018
Mathematics

contestada

How do you find the value of x in degrees.

sin 2x - 1 = 0

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jdoe0001 jdoe0001

21-02-2018

[tex]\bf sin(2x)-1=0\implies sin(2x)=1\implies sin^{-1}[sin(2x)]=sin^{-1}(1) \\\\\\ 2x=sin^{-1}(1)\implies 2x=\cfrac{\pi }{2}\implies x=\cfrac{\pi }{4}\textit{ which is }45^o[/tex]

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