Respuesta :

The molarity of a solution that contains 14 g KOH per 150 mL of solution is 1.7 m
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Answer:

1.67 M

Explanation:

Molarity =  [tex]\frac{moles}{liter}[/tex]

Moles = [tex]\frac{mass}{molar mass}[/tex]

Given

Mass of KOH =  14 g

Molar mass of KOH =  56.1056 g/mol

Moles of KOH =  [tex]\frac{14 g}{56.1056 g/mol}[/tex] = 0.25 mol

Volume of solution = 150 ml = 0.15 L (1 L = 1000 ml)

Molarity = [tex]\frac{0.25 mol}{0.15 L }[/tex]= 1.67 M

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