Respuesta :

twanp4enhr
(y^2)^5 × y^8
Use the rule:
[tex] ({ {y}^{m} })^{n} = {y}^{m \times n} [/tex]
To get:
y^10, then, use the rule:
[tex] {y}^{m} \times {y}^{n} = {y}^{m + n} [/tex]
To eventually get:
y^(10+8) = y^18 or: y18 seeing as you wrote it like that.