The given expression is :
[tex]6-\frac{2x}{3}<x-9[/tex]
Shifting the like terms to one side, and solving the equation further, we get :
= [tex]6+9<\frac{2x+3x}{3}[/tex]
= [tex]15<\frac{5x}{3}[/tex]
= [tex]45<5x[/tex]
= [tex]9<x[/tex]
or x > 9
Hence, the given inequality equation is equal to x > 9 .
