Answer:
<
Step-by-step explanation:
[tex]\dfrac{4}{9}=0.\overline{4}<0.45[/tex]
The tenths-place digits of the two numbers are the same, 4. So comparison proceeds to the hundredths place. The digit in the hundredths place of 0.4444... is 4, which is less than the digit in the hundredths place of 0.45, which is 5. Hence 4/9 < 0.45.
