Respuesta :

gmany
[tex]\text{Use:}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}\\\\..........................................\\\\\dfrac{5x^6y^2}{x^8y}=5x^{6-8}y^{2-1}=5x^{-2}y^1\\\\=\boxed{5x^{-2}y=\dfrac{5y}{x^2}}[/tex]

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