amayagonzalez1220
amayagonzalez1220
19-01-2018
Mathematics
contestada
how do I solve this problem
Respuesta :
PeytonBrainly
PeytonBrainly
19-01-2018
Answer:
sqrt 100 < sqrt 110 < sqrt 121
the square root of 100 as a perfect square is 10
the square root of 121 as a perfect square is 11
The square root in the middle is in between the perfect squares of 10^2 and 11^2.
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