Respuesta :

f'(x) = 6x^2 - 18x + 12

= 6(x^2 - 3x + 2)

= 6(x - 2)(x - 1) = 0   at turning points
at turning points  x = 1 and x = 2

f''(x) = 12x - 18  

so when x = 1 f''(x) <0  (maximum) and  when x = 2  f''(x) > 0 (minimum)



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