grgrsmb grgrsmb
  • 16-11-2017
  • Mathematics
contestada

4^2-6(2^x)-16=0


solve for x

Respuesta :

altavistard
altavistard altavistard
  • 17-11-2017
Assuming that   4^2-6(2^x)-16=0   is correct, we can rearrange it as:

-6(2^x) + 4^2 - 16=0

Are you sure it's not   6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is,   6(2^x) = 0.  Then x = 0 (answer)
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