shsbbdDnsgs274 shsbbdDnsgs274
  • 20-10-2017
  • Chemistry
contestada

How many atoms of ca are present in 8.6 mg? the atomic weight of ca is 40.08 amu?

Respuesta :

Kalahira
Kalahira Kalahira
  • 31-10-2017
One mole of any element is Avogadro's number, which is 6.02 * 10^23 atoms. One mole of Calcium is equal to its atomic weight in grams, 1 mole Ca = 40.08 x 1000 mg = 6.02 * 10^23 atoms. We have 8.6mg of Ca which means 8.6mg / 40,080mg = .00021457 of a mole of calcium. Now multiply that by Avogadro's number which gives number of atoms = 0.00021457 * 6.02 * 10^23 atoms. So the answer is 1.292 * 10^20 atoms of Ca.
Answer Link

Otras preguntas

Claudia is on a motorcycle trip. She checked the odometer at the beginning of the trip, and it showed 16,789 miles. After 15 days it showed 22,189 miles. If Cla
Three times the quantity two less than x is eight
Are honey jar spells real?
At 25.0∘C, the molar solubility of barium chromate in water is 1.10×10−5 M . Calculate the solubility in grams per liter.
Bella's cell phone cost 18$ per month plus 0.15$ for every minute she uses the phone.last month her bill was 29.25 how many minutes did she use her phone last m
Someone please answer this
Https://one feature of pure monopoly is that the firm is
Please help with the geometry question below
Where on the physical activity pyramid do sedentary activities belong?Where on the physical activity pyramid do sedentary activities belong? A. B. C. D.
A coin is tossed three times. given that at least one head appears, what is the probability that exactly two heads will appear?