Avelino Avelino
  • 19-10-2017
  • Mathematics
contestada

What is the domain of y equals -1/4x squared +1/2x minus 13/4?

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Аноним Аноним
  • 19-10-2017
If your equation is [tex]y=- \frac{1}{4} x^{2} + \frac{1}{2} x- \frac{13}{4} [/tex], then the domain is all real numbers (-∞, ∞).

If your equation is [tex]y = - \frac{1}{4 x^{2} } + \frac{1}{2x} - \frac{13}{4} [/tex],
then the domain is all real numbers except zero (-∞, 0)∪(0, ∞)
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