Respuesta :

ejelonubenedict
f'(x, y) = 8x -3xydy/dx +12y²dy/dx = 0
(12y² -3xy)dy/dx = -8x
dy/dx = -8x/[12y² -3xy]
dy/dx |(x=-1 , y=-3) : = -8(-1)/[12(-3)² - 3(-1)(-3)]
= 8/[108 -9]
=8/99

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