Respuesta :
Answer with Step-by-step explanation:
The average marks of Shahid first four papers is 88.
Let a,b,c and d be the marks in first four papers
⇒ [tex]\dfrac{a+b+c+d}{4}=88[/tex]
⇒ a+b+c+d=88×4
=352
Let marks in fifth paper be x
The average of five papers become 90
⇒ [tex]\dfrac{a+b+c+d+x}{5}=90[/tex]
⇒ a+b+c+d+x=90×5
⇒ 352+x=450 (since a+b+c+d=352)
⇒ x=450-352
⇒ x=98
Hence, Correct option is:
d.98
