[tex]P(7,2) \\
x_1=7 \\ y_1=2 \\ \\
Q(2,5) \\ x_2=2 \\ y_2=5 \\ \\
\hbox{the distance between the points:} \\
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(2-7)^2+(5-2)^2}= \\
\sqrt{(-5)^2+3^2}=\sqrt{25+9}=\sqrt{34} \approx 5.83[/tex]
The distance is 5.83 units.
