One possible equation is:
[tex] \frac{3(6-(4\div 2)^2)+9-2^3}{11-(2\times 5)} [/tex]
To double check that this is correct, work from the inside of the numerator out:
[tex] \frac{3(6-(4\div2)^2)+9-2^3}{11-(2\times5)}
\\
\\=\frac{3(6-(2)^2)+9-2^3}{11-(2\times5)}
\\
\\=\frac{3(6-4)+9-2^3}{11-(2\times5)}
\\
\\=\frac{3(2)+9-2^3}{11-(2\times5)}
\\
\\=\frac{3(2)+9-8}{11-(2\times5)}
\\
\\=\frac{6+9-8}{11-(2\times5)}
\\
\\=\frac{7}{11-(10)}
\\
\\=\frac{7}{1}=7 [/tex]
