shanesancho shanesancho
  • 16-09-2015
  • Mathematics
contestada

the perimeter of a rectangle is 13cm and its width is 11/4. find its length.

Respuesta :

ayah1
ayah1 ayah1
  • 16-09-2015
perimeter = 2 length + 2 width

P = 2(l) + 2(11/4)

[tex]13 = 2l +2* \frac{11}{4} [/tex]

[tex]13 = 2l + \frac{2}{1} * \frac{11}{4} [/tex]

[tex]13 = 2l + \frac{22}{4} [/tex]     (subtract 22/4 from each side)

[tex]13 -\frac{22}{4} = 2l[/tex]

[tex]13 -\frac{11}{2} = 2l[/tex]

[tex]\frac{26}{2} -\frac{11}{2} = 2l[/tex]

[tex]\frac{15}{2}} = 2l[/tex]

[tex]7.5 = 2l[/tex]    (divide each side by 2)

7.5 ÷ 2 = l

3.75 = l

The answer is 3.75 or [tex]3 \frac{3}{4} [/tex]


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