Respuesta :

[tex]12=3\times2\times2\\\\the\ nominator\ must\ be\ different\ from\ any\ even\ number\\and\ any\ number\ divisible\ by\ 3\\\\therefore\ your\ answer\ is:\\\\\huge\boxed{\frac{1}{12};\ \frac{5}{12};\ \frac{7}{12};\ \frac{11}{12}}[/tex]

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