Answer: -
219.375 g of NaCl is present in a 0.75 M solution with a volume of 500.0 milliliter
Explanation: -
Volume of NaCl solution = 500 mL
= 500/1000 = 0.5 L
Strength of NaCl solution = 0.75 M
Number of moles of NaCl = Strength of NaCl x Volume of NaCl
= 0.75 M x 0.5 L
= 3.75 mol
Molar mass of NaCl = 23 x 1 + 35.5 x 1
= 58.5 g / mol
Mass of NaCl = Molar mass x number of moles
= 58.5 g / mol x 3.75 mol
= 219.375 g
