Let x and y be two integers.
From the information they must satisfy the following:
x = y + 1 (two consecutive integers) EQN (1)
3x = 2y + 23 (2 times the smaller is 23 less than 3 times the larger) EQN (2)
Substituting (1) into (2) yields
3(y+1) = 2y + 34
Solving gives us y = 31 and thus x = 32
