Answer:
y=15x-ln(27)+3
by-step explanation:
Find the corresponding y-value to x=1/5⋅ln(3).
y=3
Find the first derivative and evaluate at x=1/5ln(3) and y=3 to find the slope of the tangent line.
15
Plug the slope and point values into the point-slope formula and solve for y.
y=15x−ln(27)+3
