So, the time taken by the ball to reach its maximum height is t1 = 10 s / 2 = 5 s.
The initial velocity (u) of the ball can be calculated using the first equation of motion:
u = v + gt
where:
v is the final velocity (which is 0 at the maximum height),
g is the acceleration due to gravity (9.8 m/s²), and
t is the time taken to reach the maximum height.
Substituting the given values:
u = 0 + 9.8 m/s² * 5 s = 49 m/s
So, the velocity of projection of the ball is 49 m/s.
I hope this helps!
