arirubio405 arirubio405
  • 20-08-2017
  • Mathematics
contestada

how do you solve (x+3)-15=7(x-2)+8

Respuesta :

rinatarrant rinatarrant
  • 20-08-2017
(X+3)-15=7(x-2)+8
X+3-15=7x-14+8
X-12=7x-6
-7x -7x
-6x-12=-6
12 12
-6x/-6 6/-6

Answer: x= -1
Answer Link
BenjaminG123
BenjaminG123 BenjaminG123
  • 20-08-2017
Solve using BEDMAS
(x+3)-15=7(x-2)+8
x+3-15=7(x-2)+8
x-12=7(x-2)+8
Distribute the Brackets
x-12=7(x-2)+8
x-12=7x-14+8 
x-12=7x-6
Add 12 to both sides.
(x-12)+12=(7x-6)+12
x=7x+6 
Subtract 7x from both sides
(x)-7x=(7x+6)-7x
-6x=6
Divide both sides by -6
(-6x)/-6=(6)/-6
x= -1

Hope this helps!
-Benjamin

Answer Link

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