aspenlei
aspenlei aspenlei
  • 17-08-2017
  • Mathematics
contestada

If f(x) = x^2 - 4x + 1, find the range of f(x).

{y: y ≥ -3}
{y: y ≥ 13}
all reals

Respuesta :

ghanami
ghanami ghanami
  • 17-08-2017
hello : 
y= x² - 4x + 1
calculate : x 
y = (x²-4x+4)-4+1
y+3 = (x-2)²
x exist : if   y+3 
≥ 0
y 
≥ -3
the range is : 
{y: y ≥ -3}
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