Dawson127
Dawson127
17-08-2017
Mathematics
contestada
Solve 64^(x) = 16^(x−1)
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NomiTayo
NomiTayo
17-08-2017
The answer is
x=-2
Hope this helps
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caylus
caylus
17-08-2017
Hello,
[tex]64^x=16^{x-1}\\ (2^6)^x=(2^4)^{x-1}\\ 2^{6x}=2^{4x-4}\\ 6x=4x-6\\ 2x=-4\\ x=-2\\ Proof:\\ 64^{-2}= \dfrac{1}{4096} \\ 16^{-3}= \dfrac{1}{4096} \\ [/tex]
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