Respuesta :
One way: log(A)-log(B) = log(A/B) right?
So, log( x^2-9/(x+3))
Now x^2-9 = (x+3)*(x-3), and x^2-9/(x+3) = x-3,
so log(x^2-9)-log(x+3) = log(x-3),
Indeed for all x but for x = -3, but probably no one asks you about that detail?
So, log( x^2-9/(x+3))
Now x^2-9 = (x+3)*(x-3), and x^2-9/(x+3) = x-3,
so log(x^2-9)-log(x+3) = log(x-3),
Indeed for all x but for x = -3, but probably no one asks you about that detail?
