Respuesta :

texaschic101
3x^2 = 2(x + 4)
3x^2 = 2x + 8
3x^2 - 2x - 8 = 0
(3x + 4)(x - 2) = 0

3x + 4 = 0
3x = -4
x = -4/3

x - 2 = 0
x = 2

solution is : x = -4/3 or x = 2 <==
3×y*2 = 2 (y+4)
now take it all to one side and solve it as a quadratic equation.

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